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Q.

A 2cm high object is placed on the principal axis of a concave mirror at a distance of 12 cm from the pole. If the image is inverted, real and 5.0 cm high then the location of the image and focal length of the mirror are

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a

40 cm, 8.6 cm

b

30 cm, 6.6 cm

c

30 cm, 8.6 cm  

d

10 cm ,6.6 cm

answer is B.

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Detailed Solution

u=−12 cm

m=hIh0=−52

m=−2.5 cm

m=−vu

v=2.5×−1.2=−30 cm

1f=1v+1u

f=−12×30−12+30=12×3042=607=8.6cmImage distance = 30 cm

Focal length = 8.6 cm

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