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Q.

A 2μF capacitor is charged to a potential difference 30V and the charging battery is disconnected. It is then connected to a series combination of capacitors $C_{1}$ = 2μF and $C_{2}$ = 4μF, as shown. Both $C_{1} and C_{2}$ are initially uncharged. When the switch S is closed, charge redistributes. Final potential difference across $C_{1}$ will be :

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a

12 V

b

10 V

c

8 V

d

18 V

answer is C.

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Detailed Solution

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Initial charge = 60μC

From diagram $\frac{60 - q}{2} = \frac{q}{2} + \frac{q}{4}$

$\Rightarrow q = 24 μC$

Voltage on $C_{1} = \frac{q}{2} = 12 V$

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A 2μF capacitor is charged to a potential difference 30V and the charging battery is disconnected. It is then connected to a series combination of capacitors C1 = 2μF and C2 = 4μF, as shown. Both C1 and C2 are initially uncharged. When the switch S is closed, charge redistributes. Final potential difference across C1 will be :