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A 3 Hp motor pumps out water from a well of depth 40m and fills a water tank of volume 4476 lit at a height of 20m from the ground. The running time of the motor to fill the empty tank is $(g = 10 m s^{- 2})$

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20 min

answer is D.

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Detailed Solution

$p = \frac{m g h}{t}$

$3 \times 746 = \frac{4476 \times 10 \times 60}{t}$

$t = \frac{1200}{60} = 20 \min$

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