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Q.

A 3 Kg block rests on top of a 2 kg block which is attached to a spring of force constant $K = 50 N / m$ . The maximum velocity reached by the 2 Kg block when the upper block is suddenly removed. $(g = 10 m / s^{2})$ is _______________

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answer is 5.

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Detailed Solution

$50 \times x = 5 \times 10 \Rightarrow x = 1 m$
Potential energy stored in the spring $U_{s} = \frac{1}{2} k x^{2}$
$U_{s} = \frac{1}{2} \times 50 \times 1 = 25$
$25 = \frac{1}{2} \times 2 \times V^{2} \Rightarrow V^{2} = 25 \Rightarrow V = 5 m / s$

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