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A 3 kg wet soil undergoes a separation mechanism by evaporation. After the process, the mass of the soil was found to be 1.5 kg. What is the volume of water(in cm³) present in the wet soil of the density of water is given as 1 g/cm^.3 ?

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1500 cm³

1.5 cm³

15 cm³

150 cm³

answer is A.

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Detailed Solution

Mass of wet soil = 3 kg

Mass of dry soil = 1.5 kg

Mass of water evaporated = Mass of wet soil - Mass of dry soil

= 3 kg - 1.5 kg

= 1.5 kg = 1500 g

Density = MassVolume

1 g/cm³ = 1500volume

Volume = 1500 cm³

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