Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A 3 kg wet soil undergoes a separation mechanism by evaporation. After the process, the mass of the soil was found to be 1.5 kg. What is the volume of water(in cm³) present in the wet soil of the density of water is given as 1 g/cm^.3 ?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

1500 cm³

15 cm³

150 cm³

1.5 cm³

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Mass of wet soil = 3 kg

Mass of dry soil = 1.5 kg

Mass of water evaporated = Mass of wet soil - Mass of dry soil

= 3 kg - 1.5 kg

= 1.5 kg = 1500 g

Density = MassVolume

1 g/cm³ = 1500volume

Volume = 1500 cm³

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!