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A $30 g$ bullet is fired horizontally with velocity $250 m / s,$ from a $1.5 kg$ gun. If the gun is held loosely in hand, what will be its recoil velocity?

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5 m / s

4 m / s

3 m / s

2 m / s

answer is A.

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Detailed Solution

the recoil velocity of the gun is

5 m / s

.
Recoil velocity is the speed at which the gun strikes back. The law of conservation of linear momentum suggests that

MV + mv = 0

Where M is the mass of the gun, V is the recoil velocity, m is the mass of the bullet and v is the velocity of the bullet.

M = 1.5 kg, m = 30 g = 0.03 kg, v = 250 m / s

Then the recoil velocity of the gun is;

V = \frac{mv}{M} = - \frac{0.03 \times 250}{1.5} = - 5 m / s

The negative sign indicates the direction of recoil.

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