A $30 g$ bullet is fired horizontally with velocity $250 m / s,$ from a $1.5 kg$ gun. If the gun is held loosely in hand, what will be its recoil velocity?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

5 m / s

4 m / s

3 m / s

2 m / s

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

the recoil velocity of the gun is

5 m / s

.
Recoil velocity is the speed at which the gun strikes back. The law of conservation of linear momentum suggests that

MV + mv = 0

Where M is the mass of the gun, V is the recoil velocity, m is the mass of the bullet and v is the velocity of the bullet.

M = 1.5 kg, m = 30 g = 0.03 kg, v = 250 m / s

Then the recoil velocity of the gun is;

V = \frac{mv}{M} = - \frac{0.03 \times 250}{1.5} = - 5 m / s

The negative sign indicates the direction of recoil.

JEE

NEET

Foundation JEE

Foundation NEET

CBSE