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Q.

A 30 gm bullet initially travelling at 120 m/s penetrates 12 cm into a wooden block. The average resistance exerted by the wooden block is

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a

2000 N

b

2200 N

c

2850 N

d

1800 N

answer is D.

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Detailed Solution

F=mu2−v22S=30×10−3×(120)22×12×10−2=1800N

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