Q.

A 30 kg box has to move up an inclined slope of 30°  to the horizontal at a uniform velocity of 5ms1 . If the frictional force retarding the motion is 150N, the horizontal force required to move up is (g=10ms2)   

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a

300×23N

b

300 N

c

150 N

d

300×32N

answer is A.

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Detailed Solution

Question Image

f=150N

mgsinθ+f=Fnet

300×12+150=F×32

F=300×23N

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