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Q.

A 3.0 L sample of helium gas is stored in a rigid, sealed container at 25° C and 1.0 atm pressure. The temperature is increased to 125° C. What is the new pressure of the gas?

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a

0.20 atm

b

0.75 atm

c

5.0 atm

d

1.33 atm

answer is C.

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Detailed Solution

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

$\frac{1}{298} = \frac{P_{2}}{398} P_{2} = \frac{398}{298}$

$\Rightarrow P_{2} = 1 .33 atm$

Hence, the new pressure of the gas is 1.33 atm.

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