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A 3cm cube of iron has one face at 100^oC and the other in a block of ice at 0^oC. If k of iron=0.2 CGS units and L for ice is 80cal/gm, then the amount of ice that melts in 10 minutes is (assume steady state heat transfer)

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450 gm

500 gm

900 gm

350 gm

answer is A.

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Detailed Solution

$\frac{mL}{t} = \frac{kA (θ_{1} - θ_{2})}{l} \Rightarrow \frac{80 m}{10 (60)} = \frac{0.2 x 3 x 3 x 100}{3}$
m = 450 gm

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