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A 3cm cube of iron one face at 100°C and the other in a block of ice at 0°C . If K of iron = 0.2 CGS units and L for ice is 80 cal/gm, then the amount of ice that melts in 10 minutes is (assume steady state heat transfer)

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450 g

350 g

500 g

900 g

answer is A.

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Detailed Solution

${mL}_{f} = \frac{KA (Δθ) t}{l}$

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