A 4:1 molar mixture of He and CH₄ is contained in a vessel at 20 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the weight ratio of He and CH₄ in the mixture effusing out initially?

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answer is 2.

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Detailed Solution

$\frac{r_{H e}}{r_{C H_{4}}} = \frac{P_{H e}}{P_{C H_{4}}} \sqrt{\frac{M_{C H_{4}}}{M_{H e}}} = \frac{4}{1} \sqrt{\frac{16}{4}} = \frac{8}{1}$ =it is moles ratio
Weights ratio of He and methane=8x4:16=2:1

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