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A 4 kg mass is resting on a horizontal surface. For this surface $μ_{s} = 0.6$ and $μ_{k} = 0.2$ Force required to move the body with $5 {ms}^{- 2}$ acceleration is $(g = 10 {ms}^{- 2})$

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20 N

24 N

28 N

32 N

answer is C.

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Detailed Solution

$N = m g$

$f_{k} = μ_{k} N$

$= 0.2 \times 4 \times 10$

$= 8 N$

$f - f_{k} = m a$

$f - 8 = 4 \times 5$

$f = 28 N$

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