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Q.

A 4 kg steel ball, moving with a velocity of 4 m/s collide head on with a stationary steel ball of mass 2 kg. If coefficient of restitution $e = 0.5$ , the speed of 4 kg ball after the impact is

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a

2 m/s

b

-1.5 m/s

c

2.5 m/s

d

1 m/s

answer is D.

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Detailed Solution

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Conserving momentum,

$\begin{array}{l} 4 V_{1} + 2 \times V_{2} = 4 \times 4 + 2 \times 0 \Rightarrow 2 V_{1} + V_{2} = 8...... (1) \\ Again \frac{V_{2} - V_{1}}{4 - 0} = e = \frac{1}{2} \Rightarrow V_{2} - V_{1} = 2.......... (2) \\ (1) - (2) \Rightarrow 3 V_{1} = 6 \Rightarrow V_{1} = 2 m / s \end{array}$

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