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A 49.9 g sample of barium hydroxide octahydrate $Ba (OH)_{2} \cdot 8 H_{2} O$ is dissolved in water and the solution is diluted to give a final volume of 2.50 L What is the concentration of the hydroxide ion in this solution?
$Molar mass (g {mol}^{- 1})$
$Ba (OH)_{2} \cdot 8 H_{2} O$ 315

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0.634 M

0.127 M

0.0634 M

0.190 M

answer is B.

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Detailed Solution

$\frac{Molar mass (g {mol}^{- 1})}{1}$ $= \frac{moles of hydrewide ion}{2}$

$49.9/ 315 \times 2 = moles of hydroxide ion$

$[{OH}^{-}] = \frac{\frac{99.8}{30}}{2.5} \Rightarrow 0.1267 M$

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