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Q.

A 4f orbital has

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a

one angular node

b

two angular nodes

c

three angular nodes

d

four angular nodes

answer is C.

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Detailed Solution

There are 3 nodes in the 4f orbitals.

n = 4

l = 3

No. of angular nodes = l = 3

No. of radial nodes = n – l -1 = 4 – 3 – 1 = 0

Therefore, no. of nodes = 3 + 0 = 3

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