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Q.

A 4g bullet is fired horizontally with a speed of 300m/s into 0.8kg block of wood, which is at rest on a table. If the coefficient of friction between the block and the table is 0.3, how far will the block slide approximately? $(g = 10 m / s^{2})$

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a

$0.375 m$

b

$0.19 m$

c

$0.569 m$

d

$0.758 m$

answer is D.

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Detailed Solution

As the momentum is conserved,

$\begin{array}{l} m_{1} V_{1} = m_{2} V_{2} \\ 4 \times 10^{- 3} \times 300 = 0.8 (V_{2}) \\ V_{2} = 1.5 m / \sec^{2} \\ 0^{2} - {V_{2}}^{2} = 2 (- μ g) (s) \\ s = 0.375 m \end{array}$

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A 4g bullet is fired horizontally with a speed of 300m/s into 0.8kg block of wood, which is at rest on a table. If the coefficient of friction between the block and the table is 0.3, how far will the block slide approximately? (g=10m/s2)