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A 5.25% solutions of a substance is isotonic with 1.5% solution of urea in the same solvent. If the densities of both the solutions are assumed to be equal to $1 g {cm}^{- 3}$ the molar mass of the substance will be

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$115 g {mol}^{- 1}$

$105 g {mol}^{- 1}$

$210 {mol}^{- 1}$

$90 g {mol}^{- 1}$

answer is C.

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Detailed Solution

$π_{1} = π_{2}$

$\Rightarrow C_{1} RT = C_{2} RT$

$\Rightarrow \frac{5.25}{M . wt} \times \frac{1000}{100} = \frac{1.5}{60} \times \frac{1000}{100}$

$\Rightarrow M . wt = \frac{5.25 \times 60}{1.5}$

$= 210 g {mol}^{- 1}$

Hence, the correct option (C). $210 g {mol}^{- 1}$

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