A 5.8% (wt./vol.) NaCl solution will exert an osmotic pressure closest to which one of the following: 

5.8% (wt./vol.) NaCl has molarity 

${\mathrm{C}}_{\mathrm{NaCl}}=\frac{5.8\times 1000}{58.5\times 100}=1\mathrm{M}$

Thus it will show approximately 2 M in solution $\because \mathrm{i}=2.$, strong electrolyte) 

$$\begin{gathered} \mathrm{\pi }=\mathrm{CST}\times \mathrm{i} \\ \mathrm{\pi } \mathrm{\alpha } \mathrm{Ci} \\ \mathrm{For} \mathrm{NaCl} \mathrm{Solution}, \\ \mathrm{\pi } \mathrm{\alpha } 1\mathrm{x} 2 \end{gathered}$$

$$\begin{gathered} \mathrm{For} 2 \mathrm{molal} \mathrm{sucrose} \mathrm{solution}, \\ \mathrm{\pi } \mathrm{\alpha } 2\times 1 \end{gathered}$$