A 5 amp fuse wire can withstand a maximum power of 1 W in circuit. The resistance in the fuse wire is

The amount of electricity is calculated as the product of voltage and current. Since voltage is calculated using ohm's equation as a function of resistance and current, we can use it to determine the relationship between power and resistance. Once we understand the relationship between power and resistance, we can replace the supplied numbers to get the fuse wire's resistance.

Formula used: $P=I^{2}R$
The maximum power and current for the fuse fire have been provided.
We all know that power is the amount of work done in a given amount of time, and electric power may be expressed as either an electric charge flowing continuously or an electric current moving from one place to another. In mathematics, it may be expressed as

$P=VI$

Where V denotes voltage and I denotes current.
Voltage may be calculated using Ohm's Law as the product of resistance and current.
$V=IR$
Now, if we substitute this value of voltage for power in the equation, we obtain
$P=(I R)I$
$P=I^{2}R$
Currently, in response to the query $I=5A$and $P=1 W$, When we substitute it in the formula above, we obtain,
$1W=(5A{)}^{2}R$
$R=\frac{1}{25}\Omega$
$R=0.04\Omega$

Hence, the correct answer is option 4.