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A 5% by mass of an aqueous solution of A of molar mass 342gmol^–1 is isotonic with 0.878% by mass of an aqueous solution of another substance B. The molar mass of B in gmol^–1 is

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180

120

answer is C.

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Detailed Solution

Isotonic solution has same concentration.

C₁=C₂

$\frac{5 \times 10}{342} = \frac{0.878 \times 10}{M_{B}} M_{B} = 60$

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