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Q.

A 5 C charge experiences a force of 2000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between the two points is 

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a

8 V

b

200 V

c

800 V

d

20000 V

answer is A.

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Detailed Solution

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E=Fq0=2000 N5 C=400 NC

In a uniform field, 

ΔV=E.d=(400 NC)(2×10−2m)

=8 V

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