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Q.

A 5 kg block of wood is sliding on a rough plane with an initial velocity of1 ms– 1 . If it comes to rest after travelling 5m. Calculate the average frictional force in newton

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a

5

b

500

c

0.5

d

50

answer is D.

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Detailed Solution

F = ma

F=m(v2−u22s)        (v=0),u=1m/s,s=5m,m=5 kg

F=5×(0−(1)2)2×5=−0.5 N       

                            = 0.5 N

Hence opposing force i.e., friction = 0.5 N

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