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Q.

A 5 kg body is rotated in a vertical circle with a constant speed of 4 ms−1 using a string of length 1 m, when the tension in the string is 31N, then the body will be

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a

at horizontal position

b

making an angle30° with vertical

c

at the lowest point

d

at the highest point       

answer is C.

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Detailed Solution

m=5kg, L=1m, v=4ms−1, T=31N

θ=?

T=mv2L+mgcosθ

31=5×161+5×10×cosθ

cosθ≅−1

θ=180°

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