A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time 

(i) the length of the shadow cast by another pole 10 m 50 cm high 

(ii) the height of a pole which casts a shadow 5m long.

(i)  We know that 1 m = 100 cm.

So, 5 m 60 cm = 560 cm.

3 m 20 cm = 320 cm.

10 m 50 cm = 1050 cm.

Here height of the pole and length of the shadow are in direct proportion.

Let the length of the shadow of another pole be x.
 

So, $\frac{560}{320}=\frac{1050}{x}.$

$\Rightarrow x=\frac{1050\times 320}{560}=600.$

Hence, the shadow of the another pole is 600 cm.