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A 5 V battery is connected across the points X and Y. Assume $D_{1}$ and $D_{2}$ to be normal silicon diodes. Find the current supplied by the battery if the $+ v e$ terminal of the battery is connected to point X.

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$~ 0.43 A$

$~ 0.5 A$

$~ 1.5 A$

$~ 0.86 A$

answer is A.

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Detailed Solution

Diode D₂ is in reverse bias. So , current will only flow through D₁ diode.

As the diode is normal , its potential barrier $+ 0.7 V$ is taken into account.
$i = \frac{(V - V_{2})}{R} = \frac{5 - 0.7}{10} = 0.43 A$

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