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A 50 gm sample which may contain either $H_{2} {SO}_{3}$ or ${SO}_{3}$ or any combination of the two is mixed · gm of water. The maximum oleum labelling possible of the sample formed can be :

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105 %

109 %

118 %

103.8 %

answer is D.

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Detailed Solution

9 g $H_{2} O$ reacts with 40 g ${SO}_{3}$ to form 49 g $H_{2} {SO}_{4}$ . If it was assumed that all 50 g was ${SO}_{3}$ then, 10 g of ${SO}_{3}$ is left. Hence, % labelling shall be

$[\frac{10}{59} \times \frac{100}{80} \times 18 + 100] = 103.8 %$

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