A 50 kg girl wearing high heel shoes balances herself on a single heel. The heel is circular with a diameter of 1 cm. What must be the pressure exerted by the heel on the horizontal floor?

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$5.24 \times 10^{6} {Nm}^{- 2}$

$4 \times 10^{6} {Nm}^{- 2}$

$6.24 \times 10^{6} {Nm}^{- 2}$

$5.2 \times 10^{6} {Nm}^{- 2}$

answer is C.

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Detailed Solution

$Here, m = 50 kg$
$and, radius = Diameter / 2 = 1 / 2 cm = \frac{1}{200} m$
$Pressure = \frac{Force}{Area} = \frac{mg}{{πr}^{2}}$
$= \frac{50 \times 9.8}{(22 / 7) \times (1 / 200)^{2}}$
$= 6.24 \times 10^{6} {Nm}^{- 2}$

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