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A 5000 kg rocket is set for vertical firing.The exhaust speed is 800 ms^-1.To give an upward acceleration of 20 ms^-2 , the amount of gas ejected per second to supply the needed thrust is (g =10ms^-2 )

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127.5kg s^-1

137.5kg s^-1

185.5kg s^-1

187.5kg s^-1

answer is C.

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Detailed Solution

$F = \frac{dp}{dt}, m (g + a) = \frac{dm}{dt} v \Rightarrow \frac{dm}{dt} = \frac{m (g + a)}{v}$

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