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A 56kg climber is supported in the ‘chimney’ by the friction forces exerted on his shoes and back as shown in fig. The static coefficients of friction between his shoes and the wall, and between his back and the wall are 0.80 and 0.60 respectively. Assume the walls are vertical and that frictional forces are maximum. The minimum normal force (in Newton) he must exerts is (take g = 10 m/s²)

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answer is 400.

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Detailed Solution

From free body diagrams x– component

$N_{s} - N_{w} = 0 \Rightarrow N_{s} = N_{w}$
y – component

$f_{s} + f_{w} - mg = 0$

The minimum normal force will be exerted when the static friction forces are at limit (0.8 + 0.6) N = 56x10 N = 400 N

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