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Q.

A 6.50 molal solution of KOH (aq) has a density of 1.89g cm3. The molarity of the solution is….. mol dm3. (Round off to the nearest integer). [Atomic masses: K:39.0u; o:16.0u; H:1.0 u]

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answer is 9.

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Detailed Solution

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m=1000×M(1000×d)-((GMW)solute)6.5=1000×M(1000×1.89)-(M×56)6.5(1890-56M)=1000M1890-56M=153.8M209.8M=1890M=9

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A 6.50 molal solution of KOH (aq) has a density of 1.89g cm−3. The molarity of the solution is….. mol dm−3. (Round off to the nearest integer). [Atomic masses: K:39.0u; o:16.0u; H:1.0 u]