A 7-digit number made up of all distinct digits 8,7,6,4,2, x and y is divisible by 3 the, possible number of ordered pair (x,y) is ______

Sum of the digits divisible by 3
i.e $8+7+6+4+2+\mathrm{x}+\mathrm{y}=27+\mathrm{x}+\mathrm{y}$ is divisible by 3 

$$\begin{gathered} \text{ Again since all the seven digit numbers is to have distinct digits therefore }\mathrm{x}\text{ and } \\ \mathrm{y}\text{ must be chosen from }0,1,3,5,9\text{ (excluding }8,7,6,4,2\text{ ) such that }\mathrm{x}+\mathrm{y}\text{ is a } \\ \text{ multiple of }3 \end{gathered}$$possible ordered pairs are
$\left\{(0,3)(3,0)(1,5)\left(5,1\right)(0,9)(9,0)(3,9)(9,3)\right\}$