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A $8000 kg$ engine pulls a train of $5$ wagons, each of $2000 kg$ , along a horizontal track. If the engine exerts a force of $40000 N$ and the track offers a friction force of $5000 N$ , then the net accelerating force is $N$ and acceleration of the train is $m / s^{2}$

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Detailed Solution

The net accelerating force is 35000 N and acceleration of the train is 1.94m/s2
Given:
Force applied by the engine =

40, 000 N

Friction force in the direction opposite to the motion = 5,000 N
The net force,

F = 40, 000 N - 5, 000 N

\Rightarrow

= 35, 000 N

Mass of the train,

m = 5 \times 2, 000 kg + 8, 000 kg

= 18000 kg

From Newton's second law of motion, acceleration,

a = \frac{F}{m}

\Rightarrow

\frac{35000 N}{18000 kg}

\Rightarrow

1.94 m/s2
Acceleration of the train is

1.94 m / s

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