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Q.

(a) A steady current of 2 amperes was passed through two electrolytic cells X and Y connected in series containing electrolytes FeSO4 and ZnSO4 until 2.8 g of Fe deposited at the cathode of cell X. How long did the current flow? Calculate the mass of Zn deposited at the cathode of cell Y. (Molar mass: Fe = 56 g mol–1 Zn = 65.3 g mol–1, 1F = 96500 C mol–1)

(b) In the plot of molar conductivity (𝛬m) vs square root of concentration (c1/2), following curves are obtained for two electrolytes A and B
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Detailed Solution

(a) I =2 Ampere
56 g of Fe requires =2× 96500 C
2.8 g will require =2.8×2×9650056=9650 C
Q=Itt=QI=96502=4825 s
Using Faraday's second law of electrolysis
w1w2=E1E2
Where w1 = mass of Fe and w2= mass of Zn
2.8w2=562×265.3w2=3.265g
(b) (i) A is a strong electrolyte and B is a weak electrolyte. 

(ii) For B, 𝛬m value at zero concentration cannot be obtained by extrapolation as it is a weak electrolyte. For A, the intercept will give the 𝛬m value at zero concentration.

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