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Q.

A and B alternately throw a pair of symmetrical dice. A wins if he throws 6 before B  throws 7 and B wins if he throws 7 before A throws 6. If A begins the game, the    probability of his winning is

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Detailed Solution

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a = P(A getting 6), b = P(B getting 7)

λ=(1−a)(1−b)

P(A)=a1−λ=5361−3136.56=3061=0.4918

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