A and B are ideal gases. The molecular weight of Aand B are in the ratio of 1: 4 . The pressure of a gas mixture containing equal weights of Aand B is P atm. What is the partial pressure (in atm) of B in the mixture?

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$\frac{P}{5}$

$\frac{3 P}{4}$

$\frac{P}{2}$

$\frac{P}{2.5}$

answer is A.

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Detailed Solution

$P_{1} = X_{1} \cdot P_{T}$

.No. of moles of gas is inversely proportional to molecular weight when an equal mass of gases are present.Thus, no. of moles of A and B are in the ratio 4 : 1

Mole fraction of B =1/5

Thus, P_B=P/5

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