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A and B are two photosensitive materials have their work functions are W and 2W. Light of same frequency and intensity falling on both the materials. If the maximum kinetic energy of the photo electrons are in the ratio 3:1 then the maximum kinetic energy of the electrons from A is

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3W / 2

2W / 3

answer is D.

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Detailed Solution

$\begin{array}{l} K_{1} : K_{2} = 3 : 1 K_{1} = 3 K K_{2} = K \\ h ν = w + 3 K = 2 W + K \\ 2 K = w \\ K = \frac{W}{2} \end{array}$

Kinetic energy for ‘A’ $\to 3 K = \frac{3 w}{2}$

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