A and B are two points on the axis and the perpendicular bisector, respectively, of an electric dipole. A and B are far away from the dipole and at equal distances from it. The fields at A and B are ${\vec{E}}_{A} a n d {\vec{E}}_{B} .$ Then

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

${\vec{E}}_{A} = - 2 {\vec{E}}_{B}$

$| {\vec{E}}_{B} | = \frac{1}{2} | {\vec{E}}_{A} |, a n d {\vec{E}}_{A}$ is perpendicular to ${\vec{E}}_{B}$

${\vec{E}}_{A} = {\vec{E}}_{B}$

${\vec{E}}_{A} = 2 {\vec{E}}_{B}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Electric field due to dipole at axial position is

$E_{a x i a l} = \frac{1}{4 π ε_{0}} \frac{2 p}{r^{3}} (a l o n g t h e d i p o l e m o m e n t)$

Electric field due to dipole at equatorial position

$E_{e q} = \frac{1}{4 π ε_{0}} \frac{p}{r^{3}} (o p p o s i t e d i p o l e m o m e n t)$

Hence ${\vec{E}}_{A} = - 2 {\vec{E}}_{B}$

JEE

NEET

Foundation JEE

Foundation NEET

CBSE