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Q.

A and B are two points on the axis of an electric dipole having dipole moment 'p' as shown in the figure. If the work done in slowly moving a 1µC point charge from A to B is 18 Joule, find the value of ‘p’

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a

10^-6 c-m

b

10^-5 c-m

c

10^-4 c-m

d

10^-3 c-m

answer is B.

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Detailed Solution

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$\begin{array}{l} V_{B} - V_{A} = \frac{1}{4 π \in_{o}} . \frac{p}{r^{2}} - (- \frac{1}{4 π \in_{o}} . \frac{p}{r^{2}}) = \frac{1}{4 π \in_{o}} . \frac{2 p}{r^{2}} \\ ∴ Q (V_{B} - V_{A}) = W \Rightarrow Q . \frac{1}{4 π \in_{o}} . \frac{2 p}{r^{2}} = W \\ \Rightarrow (1 \times 10^{- 6}) \times 9 \times 10^{9} \times \frac{2 p}{{(0 .1)}^{2}} = 18 \Rightarrow p = 10^{- 5} c - m \end{array}$

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