A and B are two structural isomers with their molecular formula $C_7{H}_{14}O$ and both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of $B{r}_2-H_{2}O$ . Treating either A or B with hot conc. sulphuric acid solution results in the formation of the same compound  $C\left(C_7{H}_{12}\right).$C  on treatment with $O_3$ followed by $Zn-H_{2}O$ gives $D\left(C_7{H}_{12}{O}_2\right).$ D gives $E\left(C_7{H}_{16}{O}_2\right)$ on treatment with $NaB{H}_4.$  E has only one methyl group and forms yellow ppt. with $I_2/KOH.$ Also, A gives delayed turbidity on treatment with conc. $HCl/ZnC{l}_2$ while B gives immediate turbidity on similar treatment.