a→ and b→ from the consecutive sides of regular hexagon ABCDEF List – I List – IIA)If CD→=xa→+yb→ thenP)x =-2B)If CE→=xa→+yb→ thenQ)x =-1C)If AE→=xa→+yb→ thenR)y =1D)If AD→=−xb→ thenS)y =2

AB→=a→, BC→=b→AC→=AB→+BC→=a→+b→AD→=2BC→=2

a→ and b→ from the consecutive sides of regular hexagon ABCDEF List – I List – IIA)If CD→=xa→+yb→ thenP)x =-2B)If CE→=xa→+yb→ thenQ)x =-1C)If AE→=xa→+yb→ thenR)y =1D)If AD→=−xb→ thenS)y =2

AB→=a→, BC→=b→AC→=AB→+BC→=a→+b→AD→=2BC→=2

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$\vec{a} a n d \vec{b}$ from the consecutive sides of regular hexagon ABCDEF
List – I List – II
A) If $\vec{C D} = x \vec{a} + y \vec{b} t h e n$ P) $x = - 2$
B) If $\vec{C E} = x \vec{a} + y \vec{b} t h e n$ Q) $x = - 1$
C) If $\vec{A E} = x \vec{a} + y \vec{b} t h e n$ R) $y = 1$
D) If $\vec{A D} = - x \vec{b} t h e n$ S) $y = 2$

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$A \to Q, R; B \to P, R; C \to Q, S; D \to P$

$A \to S, P; B \to Q, S; C \to Q; D \to S$

$A \to P, R; B \to Q, R; C \to P, D \to S$

$A \to P; B \to Q, S; C \to P, R; D \to Q$

answer is C.

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Detailed Solution

$\begin{array}{l} \vec{A B} = \vec{a}, \vec{B C} = \vec{b} \\ \vec{A C} = \vec{A B} + \vec{B C} = \vec{a} + \vec{b} \\ \vec{A D} = 2 \vec{B C} = 2 \end{array}$

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	List – I		List – II
A)	If $\vec{C D} = x \vec{a} + y \vec{b} t h e n$	P)	$x = - 2$
B)	If $\vec{C E} = x \vec{a} + y \vec{b} t h e n$	Q)	$x = - 1$
C)	If $\vec{A E} = x \vec{a} + y \vec{b} t h e n$	R)	$y = 1$
D)	If $\vec{A D} = - x \vec{b} t h e n$	S)	$y = 2$

a→ and b→ from the consecutive sides of regular hexagon ABCDEF List – I List – IIA)If CD→=xa→+yb→ thenP)x =-2B)If CE→=xa→+yb→ thenQ)x =-1C)If AE→=xa→+yb→ thenR)y =1D)If AD→=−xb→ thenS)y =2

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