A and B throw a die each simultaneously. The odds infavour of A not throwinga number greater than the number thrown by B is

A,  B  are throwing die alternately 

$$\begin{gathered} \mathrm{P}\left(\mathrm{A}\right)=\frac{15}{36}=\frac{5}{12} \\ \mathrm{P}\left(\overline{\mathrm{A}}\right)=\frac{7}{12} \\ \underline{\mathrm{A}} \underline{\mathrm{B}} \\ 1 2, 3, 4, 5, 6 \\ 2 3, 4, 5, 6 \\ 3 4, 5, 6 \\ 4 5, 6 \\ 5 6 \end{gathered}$$

odds in favour of

$\mathrm{A}=\mathrm{P}\left(\mathrm{A}\right) : \mathrm{P}\left(\overline{\mathrm{A}}\right)=5 : 7$