|A|=|B|=1 and angle between A¯ and B¯ is 600 Column(A) Column(B)A)|A¯+B¯|P)1B)|A¯−B¯|Q)3C)|2A¯+2B¯|R)2D)|2A¯−2B¯|S)23

|A¯+B¯|=A2+B2+2ABcosθ;|A¯−B¯|=A2+B2−2ABcosθ

|A|=|B|=1 and angle between A¯ and B¯ is 600 Column(A) Column(B)A)|A¯+B¯|P)1B)|A¯−B¯|Q)3C)|2A¯+2B¯|R)2D)|2A¯−2B¯|S)23

|A¯+B¯|=A2+B2+2ABcosθ;|A¯−B¯|=A2+B2−2ABcosθ

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$| A | = | B | = 1$ and angle between $\bar{A}$ and $\bar{B}$ is $60^{0}$
Column(A) Column(B)
A) $| \bar{A} + \bar{B} |$ P) 1
B) $| \bar{A} - \bar{B} |$ Q) $\sqrt{3}$
C) $| 2 \bar{A} + 2 \bar{B} |$ R) 2
D) $| 2 \bar{A} - 2 \bar{B} |$ S) $2 \sqrt{3}$

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$A - Q, B - P, C - S, D - R$

$A - P, B - Q, C - R, D - S$

$A - P, B - Q, C - S, D - R$

$A - R, B - S, C - Q, D - P$

answer is A.

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Detailed Solution

$| \bar{A} + \bar{B} | = \sqrt{A^{2} + B^{2} + 2 A B \cos θ}; | \bar{A} - \bar{B} | = \sqrt{A^{2} + B^{2} - 2 A B \cos θ}$

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	Column(A)		Column(B)
A)	$\| \bar{A} + \bar{B} \|$	P)	1
B)	$\| \bar{A} - \bar{B} \|$	Q)	$\sqrt{3}$
C)	$\| 2 \bar{A} + 2 \bar{B} \|$	R)	2
D)	$\| 2 \bar{A} - 2 \bar{B} \|$	S)	$2 \sqrt{3}$

|A|=|B|=1 and angle between A¯ and B¯ is 600 Column(A) Column(B)A)|A¯+B¯|P)1B)|A¯−B¯|Q)3C)|2A¯+2B¯|R)2D)|2A¯−2B¯|S)23

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$| A | = | B | = 1$ and angle between $\bar{A}$ and $\bar{B}$ is $60^{0}$
Column(A) Column(B)
A) $| \bar{A} + \bar{B} |$ P) 1
B) $| \bar{A} - \bar{B} |$ Q) $\sqrt{3}$
C) $| 2 \bar{A} + 2 \bar{B} |$ R) 2
D) $| 2 \bar{A} - 2 \bar{B} |$ S) $2 \sqrt{3}$