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A, B and C are three complexes of chromium(III) with empirical formula $C r C l_{3} O_{6} H_{12}$ . All the three complexes have water and chloride ion as ligands. Complex A doesnot react with concentrated $H_{2} S O_{4}$ , where as B and C lose 13.5% and 6.75% of their original mass, respectively,on treatment with concentrated $H_{2} S O_{4}$ . The compound A,B and C respectively are.

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$A = [C r {(H_{2} O)}_{6}] C l_{3}; B = [C r {(H_{2} O)}_{4} C l_{2}] C l .2 H_{2} O; C = [C r {(H_{2} O)}_{5} C l] C l_{2} . H_{2} O$

$A = [C r {(H_{2} O)}_{5}] C l_{3} . H_{2} O; B = [C r {(H_{2} O)}_{6}] C l_{3}; C = [C r {(H_{2} O)}_{4} C l_{2}] C l . H_{2} O$

$A = [C r {(H_{2} O)}_{5} C l] C l_{2} . H_{2} O; B = [C r {(H_{2} O)}_{4}] C l_{3}; C = [C r {(H_{2} O)}_{6} C l_{2}]$

answer is B.

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