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Q.

a¯,b¯,c¯  are unit vectors such that |a¯+b¯+3c¯|=4  . a¯,b¯=θ1,b¯,c¯=θ2  and angle between  a¯  and   c¯ is  θ3 and  θ3  varies in  [π6,2π3] ,. Then the maximum value of  cosθ1+3cosθ2= _______

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a

22

b

6

c

3

d

4

answer is B.

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Detailed Solution

 |a¯+b¯+3c¯|2=16 |a¯|2+|b¯|2+9|c¯|2+2cosθ1+6cosθ2+6cosθ3=16
 Since θ3[π6,  2π3] ,   2cosθ1+6cosθ2=56cosθ3
Maximum value of cosθ1+3cosθ2  is 4.
 

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