A, B, C, D, E and F are the elements belonging to Second group of Modern periodic table. The correct trend of abundance in earth's crust for these elements is  A > B > C > D > E > F. The element ‘D' in the sequence is

A) Atomic radius…Be<Mg<Ca<Sr<Ba ;

B) IP₁…..Be>Mg>Ca>Sr>Ra>Ba;

C) EN…..Be>Mg>Ca=Sr>Ba>Ra;

D) MP…Be>Ca>Sr>Ba>Ra>Mg ;

E) BP…Be>Ba>Ra>Ca>Sr>Mg ;

F) Density…..Ra>Ba>Sr>Be>Mg>Ca ;

G) Abundance in Earth's crust….Ca>Mg>Ba>Sr>Be>Ra ;

H) Hydration Enthalpy….Be²⁺>Mg²⁺>Ca²⁺>Sr²⁺>Ba²⁺

I) ${\mathrm{E}}_{{\mathrm{M}}^{2+}/\mathrm{M}}^{°}$ values are negative.

Most negative for Ra=Ba and least negative for Be.

J) ${\mathbf{E}}_{{\mathbf{Ra}}^{\mathbf{2}\mathbf{+}}\mathbf{/}\mathbf{Ra}}^{\mathbf{°}}(\mathrm{most} \mathrm{negative})\mathbf{=}{\mathbf{E}}_{{\mathbf{Ba}}^{\mathbf{2}\mathbf{+}}\mathbf{/}\mathbf{Ba}}^{\mathbf{°}}<{\mathrm{E}}_{{\mathrm{Sr}}^{2+}/\mathrm{Sr}}^{°}<{\mathrm{E}}_{{\mathrm{Ca}}^{2+}/\mathrm{Ca}}^{°}<{\mathrm{E}}_{{\mathrm{Mg}}^{2+}/\mathrm{Mg}}^{°}<{\mathrm{E}}_{{\mathrm{Be}}^{2+}/\mathrm{Be}}^{°}\left(\mathrm{least} \mathrm{negative}\right)$

Best reducing agent is Ra=Ba, best oxidant is Be²⁺;

K) Reducing power…Be<Mg<Ca<Sr<Ba=Ra ;

L) Oxidizing power… Be²⁺ > Mg²⁺ > Ca²⁺ > Sr²⁺ > Ba²⁺ = Ra²⁺ ;