$a,b,c,p,q,r$ are complex numbers such that $\frac{p}{a}+\frac{q}{b}+\frac{r}{c}=1+i$, and $\frac{a}{p}+\frac{b}{q}+\frac{c}{r}=0,$then $\frac{p^2}{a^2}+\frac{q^2}{b^2}+\frac{r^2}{c^2}=---$

From data m ${\left(\frac{p}{a}+\frac{q}{b}+\frac{r}{c}\right)}^2={\left[1+i\right]}^2\Rightarrow \frac{p^2}{a^2}+\frac{q^2}{b^2}+\frac{l^2}{c^2}+2\left(\frac{pq}{ab}+\frac{qr}{bc}+\frac{rp}{ca}\right)=2i$

$\Rightarrow \frac{p^2}{a^2}+\frac{q^2}{b^2}+\frac{i^2}{c^2}+2$$\frac{pwr}{abc}\left(\frac{c}{r}+\frac{a}{p}+\frac{b}{q}\right)=2i$

$\Rightarrow \frac{p^2}{a^2}+\frac{q^2}{b^2}+\frac{{\lambda }^2}{c^2}=2i\left(\because \frac{a}{p}+\frac{b}{q}+\frac{c}{r}=0\right)$