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Q.

a+babaa+ccbcb+c  is equal to

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a

a2b2c2

b

4a2bc

c

4abc

d

abc

answer is A.

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Detailed Solution

|a+babaa+ccbcb+c| R1R1R2R3 |02c2baa+ccbcb+c| |02c2baa+ccbcb+c| =2c(ab+b2bc)2b(bcc2ac) =2abc+2cb22bc22b2c+2bc2+2abc =4abc

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