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A bag B contains 4 white and 2 black. Another bag C contains 3 white balls and 5 black balls. If one ball is drawn randomly from each bag, then the probability that the two balls drawn are both white is

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$\frac{1}{4}$

$\frac{5}{24}$

$\frac{13}{24}$

$\frac{3}{4}$

answer is A.

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Detailed Solution

	Bag B	Bag C
White	4	3
Black	2	5

A=one ball drawn from each bag then both white

$P (A) = \frac{4}{6} \times \frac{3}{8} = \frac{1}{4}$

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