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A bag contains $10$ red, $5$ blue, and $7$ green balls. A ball is drawn at random. From the following choices, the probability of this ball being a not a blue ball is:

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1021

511

1722

722

answer is C.

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Detailed Solution

It is given that, a bag contains

10

red,

5

blue, and

7

green balls.
The total numbers of balls can be calculated as,

n (S) = 10 + 5 + 7

= 22

The total number of blue ball is,

n (B) = 5

Let

B

be the event of drawing a blue ball, then the probability of the event can be calculated by,

P (B) = N u m b e r of favourable outcomes T o t a l number of outcomes

P (B) = n (B) n (S)

= 522

Let

B ¯

be the event that the ball is not a blue ball, then

P (B ¯) = 1 − P (B)

= 1 − 522

= 1722

The probability is

1722

.
Hence, option 3) is correct.

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